必要性:因为\(\phi\)是正交变换且\(\phi(\alpha_i)=\beta_i\),所以
\begin{equation*}
\left(\alpha_i,\alpha_j\right)=\left(\phi(\beta_i),\phi(\beta_j)\right)=\left(\beta_i,\beta_j\right),\ i,j=1,2,\cdots ,m.
\end{equation*}
充分性:设\(\alpha_1,\dots ,\alpha_r\)是\(\alpha_1,\dots ,\alpha_m\)的一个极大无关组,则
\begin{equation*}
\det G(\alpha_1,\dots ,\alpha_r)\neq 0,
\end{equation*}
这里\(G(\alpha_1,\dots ,\alpha_r)=\left((\alpha_i,\alpha_j)\right)_{r\times r}\)。由\(\left(\alpha_i,\alpha_j\right)=\left(\beta_i,\beta_j\right)\)知
\begin{equation*}
\det G(\beta_1,\dots ,\beta_r)=\det G(\alpha_1,\dots ,\alpha_r)\neq 0,
\end{equation*}
故\(\beta_1,\dots ,\beta_r\)线性无关。
又因为\(\dim U_1^\bot=\dim U_2^\bot=n-r\),所以存在欧氏空间同构映射
\begin{equation*}
\phi_2:U_1^\bot\rightarrow U_2^\bot
\end{equation*}
注意到\(V=U_1\oplus U_1^\bot\),所以可定义\(V\)上的变换\(\phi\)如下
\begin{equation*}
\phi(\alpha+\beta)=\phi_1(\alpha)+\phi_2(\beta),\ \forall \alpha\in U_1,\ \beta\in U_1^\bot .
\end{equation*}
不难验证,\(\phi\)是\(V\)上的线性变换,下证\(\phi\)保内积。对任意\(X,Y\in V\),存在唯一的\(X_1,Y_1\in U_1, X_2,Y_2\in U_1^\bot\),使得\(X=X_1+X_2,\ Y=Y_1+Y_2\),则
\begin{equation*}
\begin{array}{ccl}
\left(\phi(X),\phi(Y)\right)&=&\left(\phi_1(X_1)+\phi_2(X_2),\phi_1(Y_1)+\phi_2(Y_2)\right)\\
&=&\left(\phi_1(X_1),\phi_1(Y_1)\right)+\left(\phi_1(X_1),\phi_2(Y_2)\right)\\
&&+\left(\phi_2(X_2),\phi_1(Y_1)\right)+\left(\phi_2(X_2),\phi_2(Y_2)\right)\\
&=&\left(\phi_1(X_1),\phi_1(Y_1)\right)+\left(\phi_2(X_2),\phi_2(Y_2)\right)\\
&=&(X_1,Y_1)+(X_2,Y_2)\\
&=&(X_1,Y_1)+(X_1,Y_2)+(X_2,Y_1)+(X_2,Y_2)\\
&=&(X,Y),
\end{array}
\end{equation*}
即\(\phi\)保内积,进而\(\phi\)是正交变换,且对\(i=1,\dots,m\),有
\begin{equation*}
\begin{array}{ll}
\phi(\alpha_i)&=\phi_1(\alpha_i)\\
&=\phi_1(a_{1i}\alpha_1+\cdots +a_{ri}\alpha_r)\\
&=a_{1i}\beta_1+\dots +a_{ri}\beta_r\\
&=\beta_i.\end{array}
\end{equation*}